Assume that a sample is used to estimate a population mean μμ.
Find the 95% confidence interval for a sample of size 65 with a
mean of 83.2 and a standard deviation of 7.7. Enter your answer as
an open-interval (i.e., parentheses)
accurate to 3 decimal places.
95% C.I. =
Solution :
Given that,
t /2,df = 1.998
Margin of error = E = t/2,df * (s /n)
= 1.998 * (7.7 / 65)
Margin of error = E = 1.908
The 95% confidence interval estimate of the population mean is,
- E < < + E
83.2 - 1.908 < < 83.2 + 1.908
81.292 < < 85.108
95% C. I. (81.292 , 85.108)
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