a) If n=10, ¯xx¯(x-bar)=33, and s=10, construct a confidence
interval at a 80% confidence level. Assume the data came from a
normally distributed population.
Give your answers to one decimal place.
< μμ <
b) In a survey, 27 people were asked how much they spent on
their child's last birthday gift. The results were roughly
bell-shaped with a mean of $46 and standard deviation of $8. Find
the margin of error at a 99% confidence level.
Give your answer to two decimal places.
c) If n=29, ¯xx¯(x-bar)=36, and s=8, find the margin of error at
a 90% confidence level
Give your answer to two decimal places.
a)
80% Confidence Interval
X̅ ± t(α/2, n-1) S/√(n)
t(α/2, n-1) = t(0.2 /2, 10- 1 ) = 1.383
33 ± t(0.2/2, 10 -1) * 10/√(10)
Lower Limit = 33 - t(0.2/2, 10 -1) 10/√(10)
Lower Limit = 28.6
Upper Limit = 33 + t(0.2/2, 10 -1) 10/√(10)
Upper Limit = 37.4
28.6 < < 37.4
b)
t critical value at 0.01 significance level with 26 df = 2.779
Margin of error = t * S / sqrt(n)
= 2.779 * 8 / sqrt(27)
= 4.28
c)
t critical value at 0.1 significance level with 28 df = 1.701
Margin of error = t * S / sqrt(n)
= 1.701 * 8 / sqrt(29)
= 2.53
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