In a survey, 17 people were asked how much they spent on their
child's last birthday gift. The results were roughly bell-shaped
with a mean of $43 and sample standard deviation of $9. Construct a
confidence interval at a 95% confidence level.
Give your answers to one decimal place.
< μμ <
Solution :
Given that,
t /2,df = 2.120
Margin of error = E = t/2,df * (s /n)
= 1.120 * ( 9/ 17)
Margin of error = E = 4.6
The 95% confidence interval estimate of the population mean is,
- E < < + E
43 - 4.6 < < 43 + 4.6
38.4 < < 47.6
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