Given table below for 2 unfair dice and its probabilities of the number of the die to come out --simulating 200 times. Calculate its -EXPECTED VALUE --
give formula --please explain.
Roll | Die 1 | Die2 |
1 |
0.1 | 0.3 |
2 | 0.1 | 0.1 |
3 | 0.2 | 0.2 |
4 | 0.3 | 0.1 |
5 | 0.2 | 0.05 |
6 | 0.1 | 0.25 |
Expected value
Give table has the Probability of occurance of the following numbers say (X) with probability p
Die 1
Roll (X) | Die 1 (p) | X*p |
1 | 0.1 | 0.1 |
2 | 0.1 | 0.2 |
3 | 0.2 | 0.6 |
4 | 0.3 | 1.2 |
5 | 0.2 | 1 |
6 | 0.1 | 0.6 |
Total | 1 | 3.7 |
Expected value = sum(X*p) = 3.7
Die 2
Roll (X) | Die 2 (p) | X*p |
1 | 0.3 | 0.3 |
2 | 0.1 | 0.2 |
3 | 0.2 | 0.6 |
4 | 0.1 | 0.4 |
5 | 0.05 | 0.25 |
6 | 0.25 | 1.5 |
Total | 1 | 3.25 |
Expected value = sum(X*p) = 3.25
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