Find the propability that x is between six and
twelve.
X~N(8,2)
Round your answers to four decimal places.
Solution:
Given, the Normal distribution with,
= 8
= 2
Find the probability that x is between six and twelve. i.e. P(6 < X < 12)
P(6 < X < 12)
= P(X < 12) - P(X < 6)
= P[(X - )/ < (12 - 8)/2] - P[(X - )/ < (6 - 8)/2]
= P[Z < 2.00] - P[Z < -1.00]
= 0.9772 - 0.1587 ..Use z table
= 0.8185
The probability that x is between six and twelve is 0.8185.
{To find P[Z < 2.00] , go to z table. See the column of z . See 2.0 in this table and see corresponding value in the row at .00 }
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