Question

Suppose that historically, 36% of applicants that are offered admittance to Georgia Southern actually enroll, while the others take offers somewhere else. If Georgia Southern will accept 9000 this coming year, what is the probability that less than 3250 will actually enroll? Use the normal approximation to the binomial.

Answer 1

Solution :

Using binomial distribution,

= n * p = 9000 * 0.36 = 3240

= n * p * q = 9000 * 0.36 * 0.64 = 45.5368

Using continuity correction ,

= P((x - ) / < (3249.5 - 3240) / 45.5368)

= P(z < 0.21)

= 0.5832

Probability = 0.5832