Let x be a discrete random variable with the following probability distribution
x: -1 , 0 , 1, 2
P(x) 0.3 , 0.2 , 0.15 , 0.35
Find the mean and the standard deviation of x
Solution:
Let mean is given by Mean = x * P(x) = [ (-1 * 0.3) + (0 * 0.2) + (1 * 0.15) + (2*0.35)],
calculations are shown in below table;
xi | pi | xi * pi | xi^2 * pi |
-1 | 0.3 | -0.3 | 0.3 |
0 | 0.2 | 0 | 0 |
1 | 0.15 | 0.15 | 0.15 |
2 | 0.35 | 0.7 | 1.4 |
Totals | 0.55 | 1.85 |
Hence mean = 0.55
Now Standard Deviation = sqrt(variance)
where variance = xi ^2 * pi - (mean)^2 = 1.85 - 0.552 = 1.5475
Hence standard deviation = sqrt ( 1.5475) = 1.2440
Thanks ! Best Luck !
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