consider a 4 out of 5 system such that r1=0.96, r2=0.98, r3=0.93, r4=0.99 and r5=0.94. compute system reliability.
consider a 4 out of 5 system such that r1=0.96, r2=0.98, r3=0.93, r4=0.99 and r5=0.94. compute system reliability.
k out of N system
k = 4, N = 5
Since the component reliabilities are not identical, we have to consider all possible mutual exclusive and exhaustive cases to calculate the system reliability,
The value of k must be at least 4 for success.
For k = 4,
number of mutually exclusive cases = 5C4 = 5
In this case, reliability is,
For k = 5,
number of mutually exclusive cases = 5C5 = 1
In this case, reliability is,
The reliability of the 4 out of 5 system is,
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