A professor tests whether the loudness of noise during an exam (low, medium, and high) is independent of exam grades (pass, fail).
The following table shows the observed frequencies for this test.
Noise Level
Low Medium High
Exam Pass 19 16 9 44
Fail 9 6 10 25
28 22 19 N = 69
(a) Conduct a chi-square test for independence at a 0.05 level of significance. (Round your answer to two decimal place)
Decide whether to retain or reject the null hypothesis. Retain
the null hypothesis. Reject the null hypothesis.
(b) Compute effect size using Cramer's V. (Round your answer to two
decimal places.)
V =
a)\
Applying Chi square test:
Expected | Ei=row total*column total/grand total | Low | Medium | High | Total |
Pass | 17.8551 | 14.0290 | 12.1159 | 44 | |
Fail | 10.1449 | 7.9710 | 6.8841 | 25 | |
total | 28 | 22 | 19 | 69 | |
chi square χ2 | =(Oi-Ei)2/Ei | Low | Medium | High | Total |
Pass | 0.073 | 0.277 | 0.801 | 1.1517 | |
Fail | 0.129 | 0.487 | 1.410 | 2.0270 | |
total | 0.2026 | 0.7643 | 2.2117 | 3.1786 | |
test statistic X2 = | 3.1786 | ||||
p value = | 0.2041 |
from above test statistic X2 =3.18
since p value >0.05, retain the null hypothesis\
b)
Cramer V=φc=√(X2/(n*(k-1)))= | 0.21 |
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