Before the hiring of an efficiency expert, the mean productivity of a firm's employees was 45.4 units per hour, with a standard deviation of 4.5 units per hour. After incorporating the changes recommended by the expert, it was found that a sample of 30 workers produced a mean of 47.5 units per hour.
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The hypothesis being tested is:
H0: µ = 45.4 units per hour
Ha: µ > 45.4 units per hour
x = 47.5 units per hour
σ = 4.5 units per hour
n = 30 workers
The test statistic, z = (x - µ)/σ/√n
z =
The p-value for z = 2.56 is 0.0053.
Since the p-value (0.0053) is less than the significance level (0.01), we can reject the null hypothesis.
Therefore, we can conclude that the mean productivity has increased.
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