Question2
(a) Prove that P(EFc) = P(E) − P(EF)
(b) Prove that P(EcFc) = 1 − P(E) – P(F) +
P(EF)
(c) Show that the probability that exactly one of the events E or F
occurs is equal to
P(E)+P(F )−2P(EF )
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