A statistics practitioner took a random sample of 40 observations from a population whose standard deviation is 15 and compute the sample mean to be 50. The 90% confidence interval for the mean will be between __________ and __________.
Solution :
Given that,
t /2,df = 1.685
Margin of error = E = t/2,df * (s /n)
= 1.685 * (15 / 40)
Margin of error = E = 4.00
The 90% confidence interval estimate of the population mean is,
- E < < + E
50 - 4.00 < < 50 + 4.00
46 < < 54
The 90% confidence interval for the mean will be between 46 and 54
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