Question

Time needed to travel to work in Japan has a normal distribution and SD Sigma. As...

Time needed to travel to work in Japan has a normal distribution and SD Sigma.

As seen, to estimate the population mean time it takes to travel to work in Japan: SE=6 mins & 99% confidence & a sample of 44.

Now calculate the sample size for SE=8 mins & 95% confidence?

Math   Statistics-And-Probability   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

In Normal distribution the Standard Error is Calculated by

  

Where sigma is the Standard deviation and n is the sample size.

Here the given information:

n= 44 and SE =6 mins

To find

n , when SE =8

By using the first set of values we will find the sigma -

  

For the New value of n When the SE =8

  

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
The travel-to-work time for residents of the 15 largest cities in the United States is reported...
The travel-to-work time for residents of the 15 largest cities in the United States is reported in the 2003 Information Please Almanac. Suppose that a preliminary simple random sample of residents of San Francisco is used to develop a planning value of 6.41 minutes for the population standard deviation. Round your answers to nearest whole number. a. If we want to estimate the population mean travel-to-work time for San Francisco residents with a margin of error of 4 minutes, what...
An Airline executive is interested in knowing the average travel time of all fights from LAX...
An Airline executive is interested in knowing the average travel time of all fights from LAX to Chicago. She takes a random sample of 50 flights from LAX to Chicago. The sample mean ( x bar ) is 180 mins. Th standard Deviation of travel of all flights from LAX to Chicago ( Sigma ) is known to be 20 mins . What is the formula to find 95% confidence interval ? ( Excel Format. )
A certain test has a population mean (mu) of 285 with a population standard deviation (sigma)...
A certain test has a population mean (mu) of 285 with a population standard deviation (sigma) or 125. You take an SRS of size 400 find that the sample mean (x-bar) is 288. The sampling distribution of x-bar is approximately Normal with mean: The sampling distribution of x-bar is approximately Normal with standard deviation: Based on this sample, a 90% confidence interval for mu is: Based on this sample, a 95% confidence interval for mu is: Based on this sample,...
Find the sample size, n, needed to estimate the mean of a normal population, μ, with...
Find the sample size, n, needed to estimate the mean of a normal population, μ, with σ = 9.25 and a maximum error of E = 3.2 at a 99% level of confidence.
Construct a 95% confidence interval for the population mean,Assume the population has a normal distribution, A...
Construct a 95% confidence interval for the population mean,Assume the population has a normal distribution, A random sample of 16 fluorescent light bulbs has a mean life of 645 hours with a standard devastion of 31 hours. From the above question calculate the 99% confidence interval for n = 16. then, Letting n= 100, calculate the 95% and 99% confidence intervals (a) What happend to the interval width from 95% to 99% (b) what happend to the interval width from...
In a random sample of eight people the mean commute time to work was 35.5 minutes,...
In a random sample of eight people the mean commute time to work was 35.5 minutes, and the SD was 7.2, find the t distribution to find the mean margin or error, given 95% confidence intervals for the population mean.
In order to estimate the mean amount of time computer users spend on the internet each​...
In order to estimate the mean amount of time computer users spend on the internet each​ month, how many computer users must be surveyed in order to be 95​% confident that your sample mean is in error by no more than 14 ​minutes? Assume that the standard deviation of the population of monthly time spent on the internet is 190 min. Use technology to find the estimated minimum required sample size. The minimum sample size required is __ computer users....
A normal distribution has µ = 60 and sigma = 8. What is the probability of...
A normal distribution has µ = 60 and sigma = 8. What is the probability of obtaining a sample mean greater the x = 62 for a sample of n = 24 scores?
a.) Given a normal distribution with σ = 0.380. Find the required sample size for a...
a.) Given a normal distribution with σ = 0.380. Find the required sample size for a 95% confidence level (estimating the mean), given a margin-of-error of 6%. b.) Given the sample results taken from a normal population distribution: mean = 4.65, σ = 0.32, and n = 17. For a 99% confidence interval, find the margin-of-error for the population mean. (use 2 decimal places) c.) Given the sample results taken from a normal population distribution: mean = 1.25, σ =...
Use the standard normal distribution or the​ t-distribution to construct a 99​% confidence interval for the...
Use the standard normal distribution or the​ t-distribution to construct a 99​% confidence interval for the population mean. Justify your decision. If neither distribution can be​ used, explain why. Interpret the results. In a random sample of 13 mortgage​ institutions, the mean interest rate was 3.59​% and the standard deviation was 0.42​%. Assume the interest rates are normally distributed. Select the correct choice below​ and, if​ necessary, fill in any answer boxes to complete your choice. A. The 99​% confidence...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT