Question

Given a population with a normal distribution, a mean of 12.6 and a standard deviation of...

Given a population with a normal distribution, a mean of 12.6 and a standard deviation of 5.35,

A.) what is the probability that a random sample of 10 will have a mean either below 9 or above 10?

B.) if you took a random sample of 12 from this population, how many observations would you expect to be above 13?

Homework Answers

Answer #1

Given that, mean (μ) = 12.6 and

standard deviation = 5.35

A) sample size (n) = 10

We want to find the probability that a random sample of 10 will have a mean either below 9 or above 10.

That is to find,

Therefore, required probability is 0.9548

B) Given that, sample size = 12

We want to find, P(X > 13)

Therefore expected number of observations above 13 is,

12 * 0.4721 = 5.6652 ≈ 6

Hence, you would expect approximately 6 observations to be above 13.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Given a normal distribution with population standard deviation of 2 and a mean of μ =...
Given a normal distribution with population standard deviation of 2 and a mean of μ = 10. If a random sample of size 69 is drawn, find P(10 ≤ x ≤ 12). Round to three decimal places.
a.) Given a normal distribution with population standard deviation of 21 and a mean of μ...
a.) Given a normal distribution with population standard deviation of 21 and a mean of μ = 29. If a random sample of size 62 is drawn, find P(29 ≤ x ≤ 31). Round to three decimal places. b.) Find the positive z value such that 89% of the standard normal curve lies between –z and z. (Use 2 decimal places.) c.) For a standard normal curve, find the area between z = 0.28 and z = 1.95. (Use 4...
The population has mean μ=29 and standard deviation σ=9. This distribution is shown with the black...
The population has mean μ=29 and standard deviation σ=9. This distribution is shown with the black dotted line. We are asked for the mean and standard deviation of the sampling distribution for a sample of size 34. The Central Limit Theorem states that the sample mean of a sample of size n is normally distributed with mean μx¯=μ and σx¯=σn√. In our case, we have μ=29, σ=9, and n=34. So, μx¯=29 and σx¯=934‾‾‾√=1.5 This distribution is shown with the red...
Given a Normal distribution with a mean (µ) of 60 and standard deviation (ᵟ) of 8,...
Given a Normal distribution with a mean (µ) of 60 and standard deviation (ᵟ) of 8, what is the probability that the sample mean (Xbar) is: Less than 57? Between 57and 62.5? Above 65? There is a 38% chance that the Xbar is above what value?
A population's distribution is normal with a mean of 18 and standard deviation of 4. A...
A population's distribution is normal with a mean of 18 and standard deviation of 4. A sample of 16 observations is selected and a sample mean computed. What is the probability that the sample mean is more than 18?
Given a normal population whose mean is 615 and whose standard deviation is 68, find each...
Given a normal population whose mean is 615 and whose standard deviation is 68, find each of the following: A. The probability that a random sample of 6 has a mean between 619 and 646. Probability = B. The probability that a random sample of 19 has a mean between 619 and 646. Probability = C. The probability that a random sample of 22 has a mean between 619 and 646. Probability =
A normal population has mean "µ" and standard deviation 12. The hypotheses to be tested are...
A normal population has mean "µ" and standard deviation 12. The hypotheses to be tested are H0: µ = 40 versus H1: µ > 40. Which would result in the highest probability of a Type II error? µ = 42; n = 100 µ = 42; n = 10 µ = 41; n = 100 µ = 41; n = 10 µ = 40.9; n = 15 If a random sample has 100 observations, the true population mean is 42,...
1. To estimate the mean of a population with unknown distribution shape and unknown standard deviation,...
1. To estimate the mean of a population with unknown distribution shape and unknown standard deviation, we take a random sample of size 64. The sample mean is 22.3 and the sample standard deviation is 8.8. If we wish to compute a 92% confidence interval for the population mean, what will be the t multiplier? (Hint: Use either a Probability Distribution Graph or the Calculator from Minitab.)
A population is normal with a mean of 80 and a standard deviation of 12. A...
A population is normal with a mean of 80 and a standard deviation of 12. A simple random sample of 50 is selected from the population. The sample mean is 78. What is the p-value if you are conducting a lower-tail (left tail) test?
A population is normal with a mean of 80 and a standard deviation of 12. A...
A population is normal with a mean of 80 and a standard deviation of 12. A simple random sample of 50 is selected from the population. The sample mean is 78. What is the p-value if you are conducting a lower-tail (left tail) test?
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT