According to a recent report,
67%
of Internet searches in a particular month used the Google search engine. Assume that a sample of
24
searches is studied. Round the answers to four decimal places.
Part 1 of 4
(a) What is the probability that exactly
21
of them used Google?
Part 2 of 4
(b) What is the probability that
16
or fewer used Google?
Part 3 of 4
(c) What is the probability that more than
21
of them used Google?
Part 4 of 4
(d) Would it be unusual if fewer than
14
used Google?
here this is binomial with parameter n=24 and p=0.67 |
a)
P(X=21)= | (nCx)px(1−p)(n-x) = | 0.0162 |
b)
P(X<=16)= | ∑x=0a (nCx)px(1−p)(n-x) = | 0.5625 |
c)
P(X>=22)=1-P(X<=21)= | 1-∑x=0x-1 (nCx)px(q)(n-x) = | 0.0053 |
d)
P(X<14)= | ∑x=0a (nCx)px(1−p)(n-x) = | 0.1322 |
since probabilty of less than 14 is not less than 0.05 , this is not an unusual event
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