A steel company is considering the relocation of one of its
manufacturing plants. The company’s executives have selected four
areas that they believe are suitable locations. However, they want
to determine if the average wages are significantly different in
any of the locations, since this could have a major impact on the
cost of production. A survey of hourly wages of similar workers in
each of the four areas is performed with the following results. Do
the data indicate a significant difference among the average hourly
wages in the three areas?
Area 1 | Area 2 | Area 3 |
---|---|---|
8 | 19 | 18 |
13 | 15 | 11 |
17 | 24 | 20 |
10 | 14 | 18 |
16 | 20 | 20 |
19 | 24 | 13 |
15 | 17 | 15 |
8 | 11 | 13 |
Step 1 of 2:
Find the value of the test statistic to test for a difference in the areas. Round your answer to two decimal places, if necessary.
Step 2 of 2:
Make the decision to reject or fail to reject the null hypothesis of equal average hourly wages in the three areas and state the conclusion in terms of the original problem. Use α=0.01.
For the given data using Anova single factor in Excel we get output as
Anova: Single Factor | ||||||
SUMMARY | ||||||
Groups | Count | Sum | Average | Variance | ||
Area 1 | 8 | 106 | 13.25 | 17.64286 | ||
Area 2 | 8 | 144 | 18 | 21.71429 | ||
Area 3 | 8 | 128 | 16 | 12 | ||
ANOVA | ||||||
Source of Variation | SS | df | MS | F | P-value | F crit |
Between Groups | 91 | 2 | 45.5 | 2.657858 | 0.09355 | 5.780416 |
Within Groups | 359.5 | 21 | 17.11905 | |||
Total | 450.5 | 23 |
So from the above output
F = ms between / ms within
F = 45.5 / 17.11905
F = 5.78
value of the test statistic = 2.66
Decision :
At α=0.01 l.o.s , df = ( 2,21 )
F critical value = 5.78
f cal < f crit
i.e., 2.66 < 5.78
so fail to reject the null hypothesis
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