Assume that a procedure yields a binomial distribution with a
trial repeated n=6 times. Find the probability of x≥4 successes
given the probability p=0.66 of success on a single trial.
(Report answer accurate to 3 decimal places.)
P(x≥4) =
The population proportion of success is p = 0.66 , also, 1 - p = 1 - 0.66 = 0.34 , and the sample size is n= 6 . We need to compute
Therefore, we get that
This implies that
which means that the probability we are looking for is
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