SAT scores are normally distributed with a mean of 1700 and a variance of 21500. What fraction of students score between 1350 and 2050 (rounded to 3 decimals)?
a)0.983
b)0.619
c)0.832
d)0.945
0.013
Solution :
Given that ,
mean = = 1700
2=21500
standard deviation = = 146.63
P(1350< x < 2050) = P[(1350-1700) /146.63 < (x - ) / < (2050-1700) /146.63 )]
= P(-2.39 < Z <2.39 )
= P(Z <2.39 ) - P(Z <-2.39 )
Using z table
= 0.9916-0.0084
= 0.893
CORRECT OPTION a)0.983
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