Question

The management for a large grocery store chain would like to determine if a new cash...

The management for a large grocery store chain would like to determine if a new cash register will enable cashiers to process a larger number of items on average than the cash register which they are currently using. Nine cashiers are randomly selected, and the number of grocery items which they can process in three minutes is measured for both the old cash register and the new cash register.

Without making any assumptions about the distribution, do the data provide conclusive evidence that the new cash register enables cashiers to process a significantly larger number of items than the old cash register? Use the Wilcoxon signed-rank test to analyze the results.

Number of Grocery Items Processed in Three Minutes
Cashier 11 22 33 44 55 66 77 88 99
Old Cash Register 6464 6666 5858 6666 6262 5757 6060 6767 7878
New Cash Register 6363 7373 6464 6868 5858 6565 6262 7777 7373

Step 1 of 2:

Find the value of the test statistic to test if the new cash register enables cashiers to process a significantly larger number of items than the old cash register. Round your answer to two decimal places, if necessary.

Step 2 of 2:

Make the decision to reject or fail to reject the null hypothesis that the number of items that the new cash register enables cashiers to process is less than or equal to the number of items that the old cash register enables cashiers to process, and state the conclusion in terms of the original problem. Use α=0.01α=0.01.

Homework Answers

Answer #1

Step 1 of 2:

-1.48

Step 2 of 2:

The p-value from the output is 0.0693.

Since the p-value (0.0693) is greater than the significance level (0.01), we cannot reject the null hypothesis.

Therefore, we cannot support the claim that the new cash register enables cashiers to process a significantly larger number of items than the old cash register.

variables: Old Cash Register - New Cash Register
10 sum of positive ranks
35 sum of negative ranks
9 n
22.500 expected value
8.441 standard deviation
-1.48 z
.0693 p-value (one-tailed, lower)
No. Data Rank
1 101 1
2 -707 7
3 -606 6
4 -202 2.5
5 404 4
6 -808 8
7 -202 2.5
8 -1010 9
9 505 5
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