Question

A genetic experiment involving peas yielded one sample of offspring consisting of 426 green peas and 164 yellow peas. Use a 0.05 significance level to test the claim that under the same circumstances, 24% of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution.

Answer #1

Given : n=426 , X=164 , The estimate of the sample proportion is ,

Hypothesis: Vs

The test statistic is ,

The p-value is ,

p-value=

The Excel function is , =2*(1-NORMDIST(7.01,0,1,TRUE))

Decision : Here , p-value <0.05

Therefore , reject the null hypothesis.

Conclusion : Hence , there is not enough evidence to support the claim that under the same circumstances, 24% of offspring peas will be yellow.

A genetic experiment involving peas yielded one sample of
offspring consisting of 442 green peas and 123 yellow peas. Use a
0.01 significance level to test the claim that under the same
circumstances, 26% of offspring peas will be yellow. Identify the
null hypothesis, alternative hypothesis, test statistic,
P-value, conclusion about the null hypothesis, and final
conclusion that addresses the original claim. Use the P-value
method and the normal distribution as an approximation to the
binomial distribution

A genetic experiment involving peas yielded one sample of
offspring consisting of 404 green peas and 142 yellow peas. Use a
0.01 significance level to test the claim that under the same
circumstances, 27% of offspring peas will be yellow. Identify the
null hypothesis, alternative hypothesis, test statistic,
P-value, conclusion about the null hypothesis, and final
conclusion that addresses the original claim. Use the P-value
method and the normal distribution as an approximation to the
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genetic experiment involving peas yielded one sample of
offspring consisting of
422
green peas and
134
yellow peas. Use a
0.01
significance level to test the claim that under the same
circumstances,
24%
of offspring peas will be yellow. Identify the null hypothesis,
alternative hypothesis, test statistic, P-value, conclusion about
the null hypothesis, and final conclusion that addresses the
original claim. Use the P-value method and the normal distribution
as an approximation to the binomial distribution.

A genetic experiment involving peas yielded one sample of
offspring consisting of 404 green peas and 134 yellow peas. Use a
0.01 significance level to test the claim that under the same
circumstances, 24% of offspring peas will be yellow. Identify the
null hypothesis, alternative hypothesis, test statistic,
P-value, conclusion about the null hypothesis, and final
conclusion that addresses the original claim. Use the P-value
method and the normal distribution as an approximation to the
binomial distribution.
what is the...

a genetic experience involving peas yielded one sample
of Offspring consisting of 408 green peas and 162 yellow pill use a
.05 significance level to test the claim that under the same
circumstances 27% of Offspring peas will be yellow identify the
null hypothesis and alternative hypothesis test statistics p-value
conclusion about the null hypothesis and final conclusion that
addresses the original claim use the P Value method and the normal
distribution as an approximation to the binomial

HW8#11
A genetic experiment involving peas yielded one sample of
offspring consisting of 448 green peas and 174 yellow peas. Use a
0.01 significance level to test the claim that under the same
circumstances, 27% of offspring peas will be yellow. Identify the
null hypothesis, alternative hypothesis, test statistic,
P-value, conclusion about the null hypothesis, and final
conclusion that addresses the original claim. Use the P-value
method and the normal distribution as an approximation to the
binomial distribution.
A. what...

A genetic experiment involving peas yielded one sample of
offspring consisting of 411 green peas and 140 yellow peas. Use a
0.01 significance level to test the claim that under the same
circumstances, 27% of offspring peas will be yellow. Identify the
null hypothesis, alternative hypothesis, test statistic,
P-value, conclusion about the null hypothesis, and final
conclusion that addresses the original claim. Use the P-value
method and the normal distribution as an approximation to the
binomial distribution.
What are the...

A genetic experiment involving peas yielded one sample of
offspring consisting of 447 green peas and 178 yellow peas. Use a
0.05 significance level to test the claim that under the same
circumstances, 27% of offspring peas will be yellow. Identify the
null hypothesis, alternative hypothesis, test statistic,
P-value, conclusion about the null hypothesis, and final
conclusion that addresses the original claim. Use the P-value
method and the normal distribution as an approximation to the
binomial distribution.
A. What are...

A genetic experiment involving peas yielded one sample
of offspring consisting of 416 green peas and 165 yellow peas. Use
a 0.01 significance level to test the claim that under the same
circumstances, 27% of offspring peas will be yellow. Identify the
null hypothesis, alternative hypothesis, test statistic,
P-value, conclusion about the null hypothesis, and final
conclusion that addresses the original claim. Use the P-value
method and the normal distribution as an approximation to the
binomial distribution.
What are the...

A genetic experiment involving peas yielded one sample of
offspring consisting of 438 green peas and 161 yellow peas. Use a
0.01 significance level to test the claim that under the same
circumstances, 24% of offspring peas will be yellow. Identify the
null hypothesis, alternative hypothesis, test statistic,
P-value, conclusion about the null hypothesis, and final
conclusion that addresses the original claim. Use the P-value
method and the normal distribution as an approximation to the
binomial distribution.
A. Upper H...

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