A genetic experiment involving peas yielded one sample of offspring consisting of 426 green peas and 164 yellow peas. Use a 0.05 significance level to test the claim that under the same circumstances, 24% of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution.
Given : n=426 , X=164 , The estimate of the sample proportion is ,
The test statistic is ,
The p-value is ,
The Excel function is , =2*(1-NORMDIST(7.01,0,1,TRUE))
Decision : Here , p-value <0.05
Therefore , reject the null hypothesis.
Conclusion : Hence , there is not enough evidence to support the claim that under the same circumstances, 24% of offspring peas will be yellow.
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