Question

A genetic experiment involving peas yielded one sample of offspring consisting of 426 green peas and 164 yellow peas. Use a 0.05 significance level to test the claim that under the same​ circumstances, 24​% of offspring peas will be yellow. Identify the null​ hypothesis, alternative​ hypothesis, test​ statistic, P-value, conclusion about the null​ hypothesis, and final conclusion that addresses the original claim. Use the​ P-value method and the normal distribution as an approximation to the binomial distribution.

Answer 1

Given : n=426 , X=164 , The estimate of the sample proportion is ,

Hypothesis: Vs  

The test statistic is ,

The p-value is ,

p-value=

The Excel function is , =2*(1-NORMDIST(7.01,0,1,TRUE))

Decision : Here , p-value <0.05

Therefore , reject the null hypothesis.

Conclusion : Hence , there is not enough evidence to support the claim that under the same​ circumstances, 24​% of offspring peas will be yellow.