Question

HW 25

A random sample of 1300 home owners in a particular city found 143 home owners who had a swimming pool in their backyard. Find a 95% confidence interval for the true percent of home owners in this city who have a swimming pool in their backyard. Express your results to the nearest hundredth of a percent. . Answer: ___ to ___ %

Answer 1

We have given here,              
              
x=143          
n=1300          
Estimate for sample proportion=0.11  
Level of significance is =1-0.95=0.05      
Z critical value(using Z table)=1.96      
              
Confidence interval formula is              


=(0.093,0.127)          

9.30 % to 12.70%