a)
t test because n<30
b)
Null Hypothesis: H0 :μ = 84
Alternative Hypothesis: Ha :μ < 84
c)
Test statistic,
t = (x bar - u)/(s/sqrt(n))
t = (76.17 - 84)/(17.52/sqrt(14))
t = -1.67221
d)
Using P-value Approach
P-value = 0.059182
e)
As P-value(0.06) >= 0.05
Since p value is greater, We fail to reject the null hypothesis.
There is not sufficient evidence to conclude that class should be discontinued because the average is below that of the rest of the school.
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