A researcher computes the following analysis of regression table. Based on the data given, what is the decision for this test at a 0.05 level of significance? (Note: Complete the table first.)
Source of Variation SS df MS F
Regression 1 28
Residual Total 118 19
___X significantly predicts Y. '
___X does not significantly predict Y.
___There is not enough information to answer this question.
Answer: X significantly predicts Y
Explanation:
Given:
Source of Variation | SS | df | MS | F |
Regression | 1 | 28 | ||
Residual | ||||
Total | 118 | 19 |
Regression:
Residual:
F-value
P-value
The p-value for the F-statistic is obtained from the F distribution table for F = 5.6, numerator degree of freedom = 1 and denominator degree of freedom = 18. (In excel use function =F.DIST.RT(5.6,1,18))
Conclusion: Since the p-value is less than 0.05 at a 5% significance level, the null hypothesis is rejected hence we can conclude that X fit the Y significantly.
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