a)
probability that we will have water shortages in exactly two days =P(X=2)= =0.2330
b)
expected value of the number of days without water in the next ten days =np=10*0.12=1.2
c)
expected number of days to have 2 days of water shortage =r/p=2/0.12=16.667
d)
probability that we have to inspect entre15 and 20 days to get two days without water =P(15<=X<=20)
=P(till 14 days exactly one day water shorate and on 15th second day+till 15 days exactly one day water shorate and on 16th second day+till 16 days exactly one day water shorate and on 17th second day+..)
=
=0.0383+0.0361+0.0339+0.0317+0.0295+0.0274=0.1968
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