The null and alternate hypotheses are:
H_{0} : μ_{d} ≤ 0
H_{1} : μ_{d} > 0
The following sample information shows the number of defective units produced on the day shift and the afternoon shift for a sample of four days last month.
Day | ||||
1 | 2 | 3 | 4 | |
Day shift | 11 | 12 | 14 | 18 |
Afternoon shift | 9 | 10 | 13 | 16 |
At the 0.050 significance level, can we conclude there are more defects produced on the day shift? Hint: For the calculations, assume the day shift as the first sample.
State the decision rule. (Round your answer to 2 decimal places.)
Compute the value of the test statistic. (Round your answer to 3 decimal places.)
What is the p-value?
Between 0.001 and 0.005
Between 0.005 and 0.01
Between 0.01 and 0.025
What is your decision regarding H_{0}?
Reject H_{0}
Do not reject H_{0}
a)
Decision rule: reject Ho if test statistic t>2.35 |
b)
value of the test statistic t =7.000
c)
Between 0.001 and 0.005
d)
Reject H_{0}
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