Question

# The null and alternate hypotheses are: H0 : μd ≤ 0 H1 : μd > 0...

The null and alternate hypotheses are:

H0 : μd ≤ 0

H1 : μd > 0

The following sample information shows the number of defective units produced on the day shift and the afternoon shift for a sample of four days last month.

 Day 1 2 3 4 Day shift 11 12 14 18 Afternoon shift 9 10 13 16

At the 0.050 significance level, can we conclude there are more defects produced on the day shift? Hint: For the calculations, assume the day shift as the first sample.

1. State the decision rule. (Round your answer to 2 decimal places.)

1. Compute the value of the test statistic. (Round your answer to 3 decimal places.)

1. What is the p-value?

• Between 0.001 and 0.005

• Between 0.005 and 0.01

• Between 0.01 and 0.025

1. What is your decision regarding H0?

• Reject H0

• Do not reject H0 a)

 Decision rule: reject Ho if test statistic t>2.35

b)

value of the test statistic t =7.000

c)

Between 0.001 and 0.005

d)

Reject H0

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