Question

The null and alternate hypotheses are:

H₀ : μ_d ≤ 0

H₁ : μ_d > 0

The following sample information shows the number of defective units produced on the day shift and the afternoon shift for a sample of four days last month.

	Day
	1	2	3	4
Day shift	11	12	14	18
Afternoon shift	9	10	13	16

At the 0.050 significance level, can we conclude there are more defects produced on the day shift? Hint: For the calculations, assume the day shift as the first sample.

1. State the decision rule. (Round your answer to 2 decimal places.)

2. Compute the value of the test statistic. (Round your answer to 3 decimal places.)

3. What is the p-value?

• Between 0.001 and 0.005

• Between 0.005 and 0.01

• Between 0.01 and 0.025

4. What is your decision regarding H₀?

• Reject H₀

• Do not reject H₀

Answer 1

a)

Decision rule: reject Ho if test statistic t>2.35

b)

value of the test statistic t =7.000

c)

Between 0.001 and 0.005

d)

Reject H₀