Question

The heights of the adults in one town have a mean of 67.5 inches and a...

The heights of the adults in one town have a mean of 67.5 inches and a standard deviation of 3.4 inches. What can you conclude from Chebyshev's theorem about the percentage of adults in the town whose heights are between 60.7 and 74.3 inches? The percentage is at least ____%. Round to a whole number if needed?

Homework Answers

Answer #1

When we don't the distribution of the sample or population we use Chebyshev's theorem to find the probability or percentage between the given values.

According to Chebyshev's theorem, the percentage between K standard deviation is calculated as:

So, we need to find the K value for heights between 60.7 and 74.3 inches as:

Since the value of K is calculated as 2 hence the percentage is calculated as:

So, the percentage of 75% adults in the town whose heights are between 60.7 and 74.3 inches.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
2. The distribution of heights of young men is approximately normal with mean 70 inches and...
2. The distribution of heights of young men is approximately normal with mean 70 inches and standard deviation 2.5 inches. a) Sketch a normal curve on which the mean and standard deviation are correctly located. (It is easiest to draw the curve first, locate the inflection points, then mark the horizontal axis.) b) What percentage of men are taller than 77.5 inches? c) Between what two heights do the middle 95% of men's heights fall? d) What percentage of men...
Men in the U.S have heights which are normally distributed with a mean of 68 inches...
Men in the U.S have heights which are normally distributed with a mean of 68 inches and a standard deviation of 2.5 inches. What percentage of men have heights between 66 inches and 69.5 inches? What height separates the shortest 6% of men from the 94% tallest men?
Assuming that the heights of college women are normally distributed with mean 60 inches and standard...
Assuming that the heights of college women are normally distributed with mean 60 inches and standard deviation 2.0 inches, answer the following questions. (Hint: Use the figure below with mean μ and standard deviation σ.) (a) What percentage of women are taller than 60 inches? % (b) What percentage of women are shorter than 60 inches? % (c) What percentage of women are between 58.0 inches and 62.0 inches? % (d) What percentage of women are between 56.0 and 64.0...
Assuming that the heights of college women are normally distributed with mean 66 inches and standard...
Assuming that the heights of college women are normally distributed with mean 66 inches and standard deviation 3.3 inches, answer the following questions. (Hint: Use the figure below with mean μ and standard deviation σ.) (a) What percentage of women are taller than 66 inches? (b) What percentage of women are shorter than 66 inches? (c) What percentage of women are between 62.7 inches and 69.3 inches? % (d) What percentage of women are between 59.4 and 72.6 inches? %
Heights for group of people are normally distributed with mean = 60 inches and standard deviation...
Heights for group of people are normally distributed with mean = 60 inches and standard deviation = 2.5 inches. Find the proportion, P, of people in the group whose heights fall into the following ranges. (Round your answers to four decimal places.) (a) Between 59 inches and 60 inches. P =___ (b) Between 54 inches and 66 inches. P =___ (c) Less than 66 inches. P =____ (d) Greater than 54 inches. P =_____ (e) Either less than 54 inches...
Assume that the heights of men are normally distributed with a mean of 69.9 inches and...
Assume that the heights of men are normally distributed with a mean of 69.9 inches and a standard deviation of 3.2 inches. The top 1% of the heights of the men will be selected for a chance to try out for a pro basketball team. What is the minimum height needed to be selected to the team? Out of 180 randomly selected adults in the United States who were surveyed, 74 exercise on a regular basis. Construct a 98% confidence...
Male heights have a mean of 70 inches and a standard deviation of 3 inches. Thus,...
Male heights have a mean of 70 inches and a standard deviation of 3 inches. Thus, a man who is 73 inches tall has a standardized score of 1. Female heights have a mean of 65 inches and a standard deviation of 2 ½ inches. These measurements follow, at least approximately, a bell-shaped curve. What do you think this means? Explain in your own words. What is the standardized score corresponding to your own height? Does this value show that...
The heights of Canadian men are normally distributed with a mean of 68.5 inches and a...
The heights of Canadian men are normally distributed with a mean of 68.5 inches and a standard deviation of 2.2 inches. According to the Expanded Empirical Rule, what percentage of Canadian men are: (a) Between 61.9 and 75.1 inches tall? (b) Over 67.026 inches tall? (c) Under 66.3 inches tall?
The heights of adult men in America are normally distributed, with a mean of 69.4 inches...
The heights of adult men in America are normally distributed, with a mean of 69.4 inches and a standard deviation of 2.66 inches. The heights of adult women in America are also normally distributed, but with a mean of 64.1 inches and a standard deviation of 2.55 inches. a) If a man is 6 feet 3 inches tall, what is his z-score (to two decimal places)? z = b) What percentage of men are SHORTER than 6 feet 3 inches?...
The heights of Canadian men are normally distributed with a mean of 66.6 inches and a...
The heights of Canadian men are normally distributed with a mean of 66.6 inches and a standard deviation of 3.6 inches. According to the empirical rule, what percentage of Canadian men are: (a) Over 63 inches tall? Answer: % (b) Between 55.8 and 77.4 inches tall? Answer: % (c) Under 69.012 inches tall? Answer: %
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT