Question

A specialist electronics company carries out its own repairs. The manager of the repair center is...

A specialist electronics company carries out its own repairs. The manager of the repair center is becoming concerned that the cost of repairs is continually increasing. She has observed the operations of the repair center and collected data relating to the number of items being repaired each day, and also the cost of repairing these items over a 50-day period. This information is presented in the following tables:

Repairs per day

Probability

1

0.08

2

0.22

3

0.38

4

0.26

5

0.06


Cost of repair ($)

Probability

5

0.28

10

0.42

15

0.22

20

0.06

25

0.02


Use the following series of random numbers to simulate the number and total daily cost of repairs carried out by the department over a 5-day period. Use the following random numbers in order (from left to right) for the simulation of repairs per day:

0.05

0.33

0.25

0.57

0.90


Use the following random numbers in order (from left to right, first row first - as you need them) for the simulation of the cost of repairs:

0.01

0.46

0.21

0.78

0.99

0.06

0.20

0.96

0.81

0.18

0.03

0.67

0.26

0.19

0.90

0.32

0.86

0.10

0.84

0.76


Please note you may find that you do not need all of the last sequence of 24 random numbers.


What is the total cost of repairs after 5 days of simulation?

Homework Answers

Answer #1

Solution

Preparatory Work

Random Number Allotment:

a)

Repairs per day

Probability

Random Numbers Allotted  

1

0.08

01 – 08

2

0.22

09 – 30

3

0.38

31 – 68

4

0.26

69 – 94

5

0.06

95 – 99, 00

b)

Cost of repair ($)

Probability

Random Numbers Allotted  

5

0.28

01 – 28

10

0.42

29 – 70

15

0.22

71 – 92

20

0.06

93– 98

25

0.02

99, 00

Actual Simulation

Day #

Repairs per day

Cost of Repairs

Total Repair Cost for the Day

Random

Number

# of Repairs

Random

Number

Cost per Repair

1

05

1

01

5

5

2

33

3

46

10

30

3

25

2

21

5

10

4

57

3

78

15

45

5

90

4

99

25

100

Total Cost = $190 ANSWER

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