Given that Z is a standard normal random variable, compute the following probabilities (to 4 decimal places).
a. P(-1.98 ≤ z ≤ 0.49)
b. P(.55 ≤ z ≤ 1.28)
c. P(-1.79 ≤ z ≤ -1.09)
(A)P(-1.98 ≤ z ≤ 0.49)
= P(Z ≤ 0.49 ) - P(Z ≤ -1.98)
Using z table,
= 0.6879 -0.0239
=0.6640
probability=0.6640
(B)P(0.55 ≤ z ≤ 1.28)
= P(Z ≤ 1.28 ) - P(Z ≤ 0.55)
Using z table,
=0.8997-0.7088
=0.1909
probability=0.1909
(c)
P(-1.79 ≤ z ≤ -1.09)
= P(Z ≤-1.09 ) - P(Z ≤ -1.79)
Using z table,
=0.1379 -0.0367
=0.1012
probability=0.1012
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