The distribution of a particular IQ test scores for persons over
16 years of age is approximately Normal with mean 100 and standard
deviation 17.
What is the probability that the average IQ score of an SRS of 60
people is 104 or higher? (Round your answer to four decimal
places.)
Solution :
Given that ,
mean = = 100
standard deviation = = 17
n = 60
= 100
= / n =17 / 60 = 2.19
P( >104 ) = 1 - P( < 104)
= 1 - P[( - ) / < (104-100) / 2.19]
= 1 - P(z < 1.83)
Using z table
= 1 - 0.9664
= 0.0336
probability= 0.0336
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