Suppose that the compressive strength of concrete is normally distributed with an unknown
mu and a known sigma of 40 (pounds per square inch). A random sample of size 19 has sample
mean 1376. Construct a 92% confidence interval (as crazy and unlikely as it seems to create
a 92% CI) for the population mean. Give answer to one decimal place.
Solution :
Given that,
Z/2 = 1.75
Margin of error = E = Z/2* ( /n)
= 1.75 * (40 / 19)
= 16.1
At 92% confidence interval estimate of the population mean is,
- E < < + E
1376 - 16.1 < < 1376 + 16.1
1359.9 < < 1392.1
(1359.9 , 1392.1)
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