In a survey, three out of four students said that courts show too much concern for criminals. Find the probability that of seventy randomly selected students
At least 56 feel that courts show too much concern
Probability that a student show too much concern for criminals
= 3/4 = 0.75
Let X be a Binomial random variable which denotes the number of students out of seventy students who show too much concern for animals
n = 70, p = 0.75
Thus , np = 52.5 and np(1-p) = 13.125
So X can be approximated to Normal distribution with
Mean = 52.5 and
standard deviation = √13.125 = 3.623
The required probability = P(X ≥ 56)
Using correction of continuity, P(X ≥ 56) = P(X > 55.5)
= P{Z > (55.5 - 52.5)/3.623}
= P(Z > 0.828)
= 0.2039
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