An experimenter is interested in estimating the dairy intake for males in a population. She took a random sample of 100 males and found the sample mean to be 755 grams per day and standard deviation to be 30 grams. . Round your solution to two significant digits after decimal.
a)
= 755, s = 30, n = 100
95% confidence interval for mean is given by.
z = 1.96
- z*s /Sqrt(n) < < + z*s /Sqrt(n)
755 -1.96 *30/sqrt(100) < < 755 +1.96 *30/sqrt(100)
755 - 5.88 < < 755 + 5.88
749.12 < < 760.88
95% confidence interval for
b) we are 95% confident for the mean gram intake of dairy products for males in the population is between 749.12 to 760.88
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