Assume that a sample is used to estimate a population mean μμ.
Find the 95% confidence interval for a sample of size 73 with a
mean of 38.6 and a population standard deviation of 13.9. Enter
your answer as an open-interval (i.e.,
parentheses) accurate to 3 decimal places.
95% C.I. =
The answer should be obtained without any preliminary rounding.
Sample size ,n = 73
Mean = u = 38.6
standard deviation,s = 13.9
Z score value at 95% CI = 1.960
Confidence Interval = u
Z*s/
Upper limit = u + Z*s/
= 38.6 + 1.960*13.9/
= 41.789
Lower limit = u - Z*s/
= 38.6 - 1.960*13.9/
= 35.411
95% C.I. = (35.411 , 41.789 )
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