Problem 15-9 (Algorithmic)
Marty's Barber Shop has one barber. Customers have an arrival rate of 2.3 customers per hour, and haircuts are given with a service rate of 4 per hour. Use the Poisson arrivals and exponential service times model to answer the following questions:
arrival rate λ= | 2.3 | |
service period=μ= | 4.00 |
a)
probability of 0 people waiting in system =(1-λ/μ)*(λ/μ)0 = | 0.4250 |
b)
probability that one customer is receiving a haircut and no one is waiting =P(1 unit in the system):
probability of 1 people waiting in system =(1-λ/μ)*(λ/μ)1 = | 0.2444 |
c)
probability of 2 people in system =(1-λ/μ)*(λ/μ)2 = | 0.1405 |
d)
probability of 3 people in system =(1-λ/μ)*(λ/μ)3 = | 0.0808 |
e)
probability that more than two customers are waiting
probability that number of customer in system is 4 or greater=Pn=>k=(λ/μ)4 = | 0.1093 |
f)
average time in queue Wq =λ/(μ(μ-λ))= | 0.3382 hours |
(please try 0.5882 if this comes wrong)
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