You wish to test the following claim (HaHa) at a significance
level of α=0.05α=0.05.
Ho:μ=82.1Ho:μ=82.1
Ha:μ>82.1Ha:μ>82.1
You believe the population is normally distributed, but you do not
know the standard deviation. You obtain a sample of size n=16n=16
with mean M=90.8M=90.8 and a standard deviation of
SD=13.9SD=13.9.
What is the p-value for this sample? (Report answer accurate to
four decimal places.)
p-value =
The p-value is...
This p-value leads to a decision to...
As such, the final conclusion is that...
The null and alternatiev hypothesis is ,
(Claim)
Since , the population standard deviation is not known.
Therefore , use t-distribution.
Now df=degrees of freedom=n-1=16-1=15
The test statistic is ,
The p-value is ,
p-value= ; The Excel function is , =TDIST(2.5036,15,1)
The p-value is less than 0.05
This p-value leads to a decision to reject the null hypothesis.
Conclusion : There is not sufficient evidence to warrant rejection of the claim that the population mean is greater than 82.1.
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