Question

The caloric consumption of 38 adults was measured and found to average 2,136. Assume the population...

The caloric consumption of 38 adults was measured and found to average 2,136. Assume the population standard deviation is 270 calories per day. Construct confidence intervals to estimate the mean number of calories consumed per day for the population with the confidence levels shown below.

a.92%

b.95%

c.99%

a. The 92% confidence interval has a lower limit of and an upper limit of .

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
The caloric consumption of 44 adults was measured and found to average 2,117. Assume the population...
The caloric consumption of 44 adults was measured and found to average 2,117. Assume the population standard deviation is 251 calories per day. Construct confidence intervals to estimate the mean number of calories consumed per day for the population with the confidence levels shown below. a. 93 % b. 96 % c. 98 % a. The 93 % confidence interval has a lower limit of and an upper limit of
The caloric consumption of 37 adults was measured and found to average 2 comma 199. Assume...
The caloric consumption of 37 adults was measured and found to average 2 comma 199. Assume the population standard deviation is 259 calories per day. Construct confidence intervals to estimate the mean number of calories consumed per day for the population with the confidence levels shown below. a. 91 % b. 96 % c. 97 % a. The 91 % confidence interval has a lower limit of nothing and an upper limit of ____. ​(Round to one decimal place as​...
Pinworm: In a random sample of 810 adults in the U.S.A., it was found that 84...
Pinworm: In a random sample of 810 adults in the U.S.A., it was found that 84 of those had a pinworm infestation. You want to find the 99% confidence interval for the proportion of all U.S. adults with pinworm. (a) What is the point estimate for the proportion of all U.S. adults with pinworm? Round your answer to 3 decimal places. (b) Construct the 99% confidence interval for the proportion of all U.S. adults with pinworm. Round your answers to...
A cruise company would like to estimate the average beer consumption to plan its beer inventory...
A cruise company would like to estimate the average beer consumption to plan its beer inventory levels on future​ seven-day cruises.​ (The ship certainly​ doesn't want to run out of beer in the middle of the​ ocean!) The average beer consumption over 17 randomly selected​ seven-day cruises was 82,357 bottles with a sample standard deviation of 4,492 bottles. Complete parts a and b below. a. Construct a 99​% confidence interval to estimate the average beer consumption per cruise. Answer: The...
In a random sample of 830 adults in the U.S.A., it was found that 84 of...
In a random sample of 830 adults in the U.S.A., it was found that 84 of those had a pinworm infestation. You want to find the 95% confidence interval for the proportion of all U.S. adults with pinworm. (a) What is the point estimate for the proportion of all U.S. adults with pinworm? Round your answer to 3 decimal places. (b) Construct the 95% confidence interval for the proportion of all U.S. adults with pinworm. Round your answers to 3...
A cruise company would like to estimate the average beer consumption to plan its beer inventory...
A cruise company would like to estimate the average beer consumption to plan its beer inventory levels on future​ seven-day cruises.​ (The ship certainly​ doesn't want to run out of beer in the middle of the​ ocean!) The average beer consumption over 20 randomly selected​ seven-day cruises was 81,654 bottles with a sample standard deviation of 4,537 bottles. Complete parts a and b below. a. Construct a 95​% confidence interval to estimate the average beer consumption per cruise. The 95​%...
Pinworm: In a random sample of 790 adults in the U.S.A., it was found that 76...
Pinworm: In a random sample of 790 adults in the U.S.A., it was found that 76 of those had a pinworm infestation. You want to find the 99% confidence interval for the proportion of all U.S. adults with pinworm. (a) What is the point estimate for the proportion of all U.S. adults with pinworm? Round your answer to 3 decimal places.    (b) What is the critical value of z (denoted zα/2) for a 99% confidence interval? Use the value...
A cruise company would like to estimate the average beer consumption to plan its beer inventory...
A cruise company would like to estimate the average beer consumption to plan its beer inventory levels on future​ seven-day cruises.​ (The ship certainly​ doesn't want to run out of beer in the middle of the​ ocean!) The average beer consumption over 16 randomly selected​ seven-day cruises was 81,867 bottles with a sample standard deviation of 4,522 bottles. Complete parts a and b below. a. Construct a 99​% confidence interval to estimate the average beer consumption per cruise. The 99​%...
A cruise company would like to estimate the average beer consumption to plan its beer inventory...
A cruise company would like to estimate the average beer consumption to plan its beer inventory levels on future seven-day cruises. (The ship certainly doesn't want to run out of beer in the middle of the ocean!) The average beer consumption over 14 randomly selected seven-day cruises was 81,619 bottles with a sample standard deviation of 4,521 bottles. Construct an 80% confidence interval to estimate the average beer consumption per cruise. The 80 % confidence interval to estimate the average...
In a random sample of 830 adults in the U.S.A., it was found that 84 of...
In a random sample of 830 adults in the U.S.A., it was found that 84 of those had a pinworm infestation. You want to find the 95% confidence interval for the proportion of all U.S. adults with pinworm. (a) What is the point estimate for the proportion of all U.S. adults with pinworm? Round your answer to 3 decimal places. (b) What is the critical value of z (denoted zα/2) for a 95% confidence interval? Use the value from the...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT