Question

Let X be a random variable with the pmf p(x) which is positive at x=1;0;1, and...

Let X be a random variable with the pmf p(x) which is positive at x=1;0;1, and zero elsewhere. If E(X^3) = 0 andE(X^2) =p(0),what is p(1)?

Homework Answers

Answer #1

You have written that x takes the values 1,0,1 but that is not possible. 1 cannot occur twice. It should be -1,0,1. So i Have provided the solution accordingly

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Let X be a discrete random variable with the pmf p(x): 0.8 for x=-4, 0.1 for...
Let X be a discrete random variable with the pmf p(x): 0.8 for x=-4, 0.1 for x=-2, 0.07 for x=0, 0.03 for x=2 a) Find E(2/X) b) Find E(lXl) c) Find Var(lXl)
Let X be a discrete random variable with probability mass function (pmf) P (X = k)...
Let X be a discrete random variable with probability mass function (pmf) P (X = k) = C *ln(k) for k = e; e^2 ; e^3 ; e^4 , and C > 0 is a constant. (a) Find C. (b) Find E(ln X). (c) Find Var(ln X).
Given a random variable X has the following pmf: X -1 0 1 P[X] 0.25 0.5...
Given a random variable X has the following pmf: X -1 0 1 P[X] 0.25 0.5 0.25 Define Y = X2 & W= Y+2. Which one of the following statements is not true? A) V[Y] = 0.25. B) E[XY] = 0. C) E[X3] = 0. D) E[X+2] = 2. E) E[Y+2] = 2.5. F) E[W+2] = 4.5. G) V[X+2] = 0.5. H) V[W+2] = 0.25. I) P[W=1] = 0.5 J) X and W are not independent.
Given a random variable X has the following pmf: X -1 0 1 P[X] 0.25 0.5...
Given a random variable X has the following pmf: X -1 0 1 P[X] 0.25 0.5 0.25 Define Y = X2 & W= Y+2. Which one of the following statements is not true? A) V[Y] = 0.25. B) E[XY] = 0. C) E[X3] = 0. D) E[X+2] = 2. E) E[Y+2] = 2.5. F) E[W+2] = 4.5. G) V[X+2] = 0.5. H) V[W+2] = 0.25. I) P[W=1] = 0.5 J) X and W are not independent.
Let X, Y be two random variables with a joint pmf f(x,y)=(x+y)/12 x=1,2 and y=1,2 zero...
Let X, Y be two random variables with a joint pmf f(x,y)=(x+y)/12 x=1,2 and y=1,2 zero elsewhere a)Are X and Y discrete or continuous random variables? b)Construct and joint probability distribution table by writing these probabilities in a rectangular array, recording each marginal pmf in the "margins" c)Determine if X and Y are Independent variables d)Find P(X>Y) e)Compute E(X), E(Y), E(X^2) and E(XY) f)Compute var(X) g) Compute cov(X,Y)
1. Let X be a discrete random variable with the probability mass function P(x) = kx2...
1. Let X be a discrete random variable with the probability mass function P(x) = kx2 for x = 2, 3, 4, 6. (a) Find the appropriate value of k. (b) Find P(3), F(3), P(4.2), and F(4.2). (c) Sketch the graphs of the pmf P(x) and of the cdf F(x). (d) Find the mean µ and the variance σ 2 of X. [Note: For a random variable, by definition its mean is the same as its expectation, µ = E(X).]
Let f(x) = (1/2)^x, x = 1,2,3,... be the PMF of the random variable X. Find...
Let f(x) = (1/2)^x, x = 1,2,3,... be the PMF of the random variable X. Find the MGF, mean, and variance of X.
A. (i) Consider the random variable X with pmf: pX (−1) = pX (1) = 1/8,...
A. (i) Consider the random variable X with pmf: pX (−1) = pX (1) = 1/8, pX (0) = 3/4. Show that the Chebyshev inequality P (|X − μ| ≥ 2σ) ≤ 1/4 is actually an equation for this random variable. (ii) Find the pmf of a different random variable Y that also takes the values {−1, 0, 1} for which the Chebyshev inequality P (|X − μ| ≥ 3σ) ≤ 1/9 is actually an equation.
Let X be a r.v with pmf p(x) = c( 2 /3 )^ x , x...
Let X be a r.v with pmf p(x) = c( 2 /3 )^ x , x = 0, 1, 2, 3, ... (infinitely many values of x) (a) Find the constant c. (b) With the constant you find in (a), find the mean E(X)
Let N be a positive integer random variable with PMF of the form pN(n)=12⋅n⋅2−n,n=1,2,…. Once we...
Let N be a positive integer random variable with PMF of the form pN(n)=12⋅n⋅2−n,n=1,2,…. Once we see the numerical value of N , we then draw a random variable K whose (conditional) PMF is uniform on the set {1,2,…,2n} . 1. Find joint PMF pN,K(n,k) For n=1,2,… and k=1,2,…,2n 2. Find the marginal PMF pK(k) as a function of k . For simplicity, provide the answer only for the case when k is an even number. For k=2,4,6,… 3. Let...