Fill in the
P(X=x )values in the table below to give a legitimate probability distribution for the discrete random variable
X,whose possible values are -3,-1,4,5,6
Value of x
-3,-1,4,5,6
P (X=x)
0.18,0.15,0.17,___,___
We are given the probability for 3 of the 5 values here.
The sum of the given 3 probabilities here is computed as:
P(X = -3) + P(X = -1) + P(X = 4) = 0.18 + 0.15 + 0.17 = 0.5
As the sum of all probabilities should be 1, therefore we have
here:
P( X = 5) + P(X = 6) = 0.5
Both the values should lie between 0 and 1.
An example discrete distribution here is given as:
P(X = -3) = 0.18,
P(X = -1) = 0.15,
P(X = 4) = 0.17,
P(X = 5) = 0.25,
P(X = 6) = 0.25
This is one of the infinite possible probability distribution here.
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