Question

Cans of soda vary slightly in weight. Given below are the measured weights of seven cans, in pounds. Find the mean and median of these weights. Which, if any, of these weights would be considered an outlier? What are the mean and median weights if the outlier is excluded?

0.81590.8159 |
0.81940.8194 |
0.81650.8165 |
0.81760.8176 |
0.79110.7911 |
0.81420.8142 |
0.81230.8123 |

Find the mean and median of the weights.

The mean is

What is the mean Round to four decimal places as needed

What is the median? Round to 4 decimal places as needed.

Answer #1

Sum of all the weights = 0.8159+0.8194+0.8165+0.8176+0.7911+0.8142+0.8123 = 5.687

Mean = 5.687/7 = 1.4218

When arranged in ascending order, the middle term ie., 4th term is median.

Ascending order => 0.7911,0.8123,0.8142,0.8159,0.8165,0.8176,0.8194. So, median = 4th term = 0.8159.

Outlier is 0.7911 because it is very far from mean and median. When the outlier is excluded,

Mean = (0.8159+0.8194+0.8165+0.8176+0.8142+0.8123)/6 = 4.8959/6 = 0.8160

Median = average of 3rd and 4th term = (0.8159+0.8165)/2 = 0.8162

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