8.
Use the pulse rates in beats per minute (bpm) of a random sample of adult females listed in the data set available below to test the claim that the mean is less than76
bpm. Use a 0.10 significance level.
Pulse Rate (bpm) |
||
85 |
58 |
|
65 |
87 |
|
85 |
98 |
|
97 |
101 |
|
74 |
64 |
|
40 |
99 |
|
67 |
68 |
|
100 |
64 |
|
100 |
68 |
|
44 |
60 |
|
61 |
36 |
|
56 |
96 |
|
89 |
68 |
|
40 |
82 |
|
51 |
44 |
|
35 |
77 |
|
72 |
71 |
|
101 |
79 |
|
89 |
68 |
|
57 |
90 |
|
52 |
102 |
|
52 |
99 |
|
83 |
105 |
|
48 |
82 |
|
61 |
78 |
Assuming all conditions for conducting a hypothesis test are met, what are the null and alternative hypotheses?
A.
H0:
μ=76
bpm
H1:
μ>76
bpm
B.
H0:
μ=76
bpm
H1:
μ≠76
bpm
C.
H0:
μ>76
bpm
H1:
μ<76
bpm
D.
H0:
μ=76
bpm
H1:
μ<76
bpm
Determine the test statistic. (Round to two decimal places as needed.)
Determine the P-value (Round to three decimal places as needed.)
State the final conclusion that addresses the original claim.
Fail to reject
Reject
H0.
There is
▼
sufficient
not sufficient
evidence to conclude that the mean of the population of pulse rates for adult females is
▼
not
less than
greater than
76
bpm.
for Hypothesis: option D is correct
null hypothesis: HO: μ | = | 76 | |
Alternate Hypothesis: Ha: μ | < | 76 |
population mean μ= | 76 | |||
sample mean 'x̄= | 72.960 | |||
sample size n= | 50 | |||
std deviation s= | 20.1301 | |||
std error ='sx=s/√n=20.1301479662435/√50= | 2.8468 | |||
t statistic ='(x̄-μ)/sx=(72.96-76)/2.847= | -1.07 | |||
p value = | 0.145 | from excel: tdist(1.068,49,1) |
Fail to reject Ho ; There is not sufficient evidence to conclude that the mean of the population of pulse rates for adult females is less than 76 bpm
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