Question

Suppose 59% of the students in a university are baseball players.

If a sample of 632 students is selected, what is the probability that the sample proportion of baseball players will be greater than 63%? round to four decimal places.

Answer 1

Probability = p = 0.59

Sample size = n = 632

We have to find the probability that the sample proportion of baseball players will be greater than 63%.

That is we have to find P( > 0.63)

For finding this probability we have to find a z score.

That is we have to find P(Z > 2.08)

P(Z > 2.08) = 1 - P(Z < 2.08) = 1 - 0.9814 = 0.0186

( From z table)