No Interaction |
Low Interaction |
Moderate Interaction |
High Interaction |
2 |
3 |
3 |
9 |
4 |
3 |
10 |
10 |
4 |
5 |
2 |
8 |
4 |
1 |
1 |
5 |
7 |
2 |
2 |
8 |
8 |
2 |
3 |
4 |
1 |
7 |
10 |
9 |
1 |
8 |
8 |
4 |
8 |
6 |
4 |
1 |
4 |
5 |
3 |
8 |
solution:-
excel data analysis tool for one factor anova, steps are: write data >memu>data>data analysis>anova:one factor>enter label>ok,and following o/p obtained.
Anova: Single Factor | ||||||
SUMMARY | ||||||
Groups | Count | Sum | Average | Variance | ||
no | 10 | 43 | 4.3 | 6.9 | ||
low | 10 | 42 | 4.2 | 5.511111 | ||
moderate | 10 | 46 | 4.60 | 11.60 | ||
high | 10 | 66 | 6.60 | 8.49 | ||
ANOVA | ||||||
Source of Variation | SS | df | MS | F | P-value | F crit |
Between Groups | 38.275 | 3 | 12.758 | 1.570 | 0.2134 | 2.866 |
Within Groups | 292.500 | 36 | 8.125 | |||
Total | 330.775 | 39 |
H_{0:} µ1=µ2=µ3=µ4
H_{1} : not all means are equal
F stat = 1.57
p valve =0.2134
p valve>α=0.05,do not reject Ho
there is no significant difference among different types of interaction.
No further post hoc test are required.
thanks..
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