People were polled on how many books they read the previous year. Initial survey results indicate that sequals 10.9 books. Complete parts (a) through (d) below.
a)
suppose this is the question
How many subjects are needed to estimate the mean number of books read the previous year within 6 books with 90%confidence?
n = z^2* s^2/e^2
now s = 10.9
e = 6 {it could be different number in your case)
z =1.96 for 95% and 1.645 for 90% level and 2.576 for 99%
n = (1.645 * 10.9/6)^2 = 8.93
= 9
b)
if e = 3
then n = (1.645 * 10.9/3)^2 = 35.722
= 36
c)
Doubling the required accuracy nearly quadruples the sample size.
d)
for 99%
e = 6
n = (2.576 * 10.9/6)^2 = 21.899
n = 22
Increasing the level of confidence increases the sample size required. For a fixed margin of error, greater confidence can be achieved with a larger sample size.
Please give me a thumbs-up if this helps you out. Thank you! :)
Please look below in comments for help in other parts/question
Get Answers For Free
Most questions answered within 1 hours.