Question

We are interested in estimating the proportion of people that can identify Nebraska but not Vermont. In a class of 55 students, each student was requested to select a sample of 6 people, show each person a map of the US and ask the person to identify the states of Vermont and Nebraska. The following numbers are the counts that each student got, that is, each number is the count of people in the student sample of 6, that could identify Nebraska but not Vermont.  

4
4
5
5
0
1
0
1
1
0
0
2
0
0
3
0
0
0
2
0
2
0
0
0
1
1
0
0
0
0
2
0
1
0
0
0
0
0
0
1
0
0
0
2
0
0
0
0
0
0
0
1
0
1
0


Note: You can cut and past these numbers into an excel spreadsheet to help you calculate the mean and the standard deviation and compute the confidence interval. If you have trouble pasting them, paste them to a text file first and then copy from there.

When we collect all the students' data, we have a sample size of 6x55=330.

Of the sample of 330 people, what proportion were able to locate Nebraska but not Vermont?  

Find a 95% confidence interval for the true proportion of people that can locate Nebraska but not Vermont. The 95% confidence interval is ( ,   ).  
(Round answers to two places after the decimal.)

Answer 1

Solution:

Of the sample of 330 people, what proportion were able to locate Nebraska but not Vermont?

Answer: The proportion who were able to locate Nebraska but not Vermont is:

Find a 95% confidence interval for the true proportion of people that can locate Nebraska but not Vermont.

The 95% confidence interval is: