A couple wants to have children until they have their first daughter, but they will not have more than three children. If the chance of having a child of a particular gender is the same (0.5), find the probability that they will have more boys than girls (note that the sample points are not necessary equiprobable).
Probability that the couple have girl as their first child = 1/2
(In this case they will not have more child's)
Probability that the couple have boy as first child and girl as second child = 1/2 * 1/2 = 1/4
Probability that the couple have boy as first and second child and girl as third child = 1/2 * 1/2 * 1/2 = 1/8
Probability that the couple have boy as all the first three child = 1/8
Thus, in case 3 and 4 the couple will have more boys than girls.
So the required probability = 1/8 + 1/8 = 1/4
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