Height data, collected from a statistics class, has a mean x=68.21 inches, and a standard deviation of s= 4.01 inches. The sample size of the data was n=36 . Suppose the data collected could be considered a random sample of UCLA students.
What sample size would be needed for a 90% confidence interval to have a margin of error,B , within .25?
Give your answer as a whole number.
Solution :
Given that,
standard deviation =s = =4.01
Margin of error = E = 0.25
At 90% confidence level of z is
= 1 - 90%
= 1 - 0.90 =0.10
/2
= 0.05
Z/2
= Z0.05 = 1.645
sample size = n = [Z/2* / E] 2
n = ( 1.645 * 4.01 / 0.25 )2
n =696.21
Sample size = n =696
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