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A professor has been teaching accounting for over 20 years. From her experience she knows that...

A professor has been teaching accounting for over 20 years. From her experience she knows that 75% of her students do homework regularly. 70% of her students pass the course and 65% of her students do homework and also pass the course. If a student is randomly selected from her class, what is the probability that the student would:

a. Do the homework regularly or pass the course?

b. Do not do the homework regularly?

c. Pass the course, given that he does the homework regularly?

d. Are “do the homework regularly” and “pass the course” independent? Why or why not?

Math   Statistics-And-Probability   
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Answer #1

A) P(do homework regularly or pass the course) = P(do homework regularly) + P(pass the course) - P(do homework regularly and pass the course)

= 0.75 + 0.7 - 0.65

= 0.8

B) P(do not do the homework regularly) = 1 - P(do the home regularly) = 1 - 0.75 = 0.25

C) P(pass the course | does homework regularly) = P(does homework regularly and pass the course) / P(does homework regularly)

= 0.65 / 0.75

= 0.8667

D) no they are not independent events. Because P(pass the course | does homework regularly) is not equal to P(pass the course)

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