1.Menstrual cycle length. Menstrual cycle lengths (days) in an SRS of nine women are as follows: {31, 28, 26, 24, 29, 33, 25, 26, 28}. Use this data to test whether mean menstrual cycle length differs significantly from a lunar month using a one sample t-test. (A lunar month is 29.5 days.) Assume that population values vary according to a Normal distribution. Use a two-sided alternative. Show all hypothesis-testing steps.
olution:
x | x2 |
31 | 961 |
28 | 784 |
26 | 676 |
24 | 576 |
29 | 841 |
33 | 1089 |
25 | 625 |
26 | 676 |
28 | 784 |
∑x=250 | ∑x2=7012 |
Mean ˉx=∑xn
=31+28+26+24+29+33+25+26+28/9
=250/9
=27.7778
Sample Standard deviation S=√∑x2-(∑x)2nn-1
=√7012-(250)29/8
=√7012-6944.4444/8
=√67.5556/8
=√8.4444
=2.9059
This is the two tailed test .
The null and alternative hypothesis is ,
H0 : = 29.5
Ha : 29.5
Test statistic = t
= ( - ) / S / n
= (27.78 -29.5) / 2.90 / 9
= -1.779
Test statistic = t = -1.779
P-value =0.1131
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