Find the minimum sample size n needed to estimate
muμ
for the given values of c,
sigmaσ,
and E.
cequals=0.95
sigmaσequals=8.2
and
Eequals=1
Assume that a preliminary sample has at least 30 members.
Solution
standard deviation = =8.2
Margin of error = E = 1
At 95% confidence level the z is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
Z/2 = Z0.025 = 1.96
sample size = n = [Z/2* / E] 2
n = ( 1.96* 8.2 / 1 )2
n =258.309
Sample size = n =259
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