Question

The diameter of a pipe is normally distributed, with a mean of 0.6 inch and a variance of 0.0016. What is the probability that the diameter of a randomly selected pipe will exceed 0.632 inch? (You may need to use the standard normal distribution table. Round your answer to four decimal places.)

Answer 1

Solution:

Given that

The diameter of pipe is normally distribution with mean = 0.6

variance = 0.0016

x = 0.632

We have to find the probability that the diameter of a randomly selected pipe will exceed 0.632 inch.

Now to find the Z- score

we know that

From the table the value between z=0 and z=0.8 is 0.2881

Now The probability that the diameter will exceed 0.632 inch is given by.

Therefore the probability that the diameter of a randomly selected pipe will be exceed 0.632 inch is 0.5119.

variance = 0.0016

x = 0.632

We have to find the probability that the diameter of a randomly selected pipe will exceed 0.632 inch.

Now to find the Z- score